440Hz(每秒震動一次)--> A4，f = 440*(2^(n/12)) Hz，n表示與A4相差幾個半音。
例如C5其距離A4有3個半音的距離A4 → A♯4 → B4 → C5，且高於A4，所以C5的n=3，f = 440*2^(3/12) Hz ~ 523.2511Hz。若所求的音低於A4，則n為負。依此公式，我們可看出相差一個或多個八度音，n此時為12的倍數(8度音包含12個半音)，所以簡化 f = 440*2^(±k)Hz，故其頻率差距為整數倍。
數字法
|
A的頻率[HZ]
|
|---|---|
C-1 – B-1
|
13.75
|
C0 – B0
|
27.5
|
C1 – B1
|
55
|
C2 – B2
|
110
|
C3 – B3
|
220
|
C4 – B4
|
440
|
C5 – B5
|
880
|
C6 – B6
|
1760
|
C7 – B7
|
3520
|
C8 – B8
|
7040
|
C9 – B9
|
14080
|
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也可在Android上用耶!
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